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Hey what's 10 & 11 y'all im dumb

Hey what's 10 & 11 y'all im dumb-example-1

2 Answers

5 votes

Answer:

10 is 2.89g/ml

11 in attachment

Step-by-step explanation:

10. D=M/V

M=250G-120G=130G

V=75ML-30ML=45ML

D=130/45=2.89g/ml

Hey what's 10 & 11 y'all im dumb-example-1
User Prgrmr
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10. The density of the rock is 2.89 g/mL.

11. The fluids will be layered as follows:

  • Bottom: Fluid A (1.03 g/mL)
  • Middle: Fluid C (0.9 g/mL)
  • Top: Fluid B (0.79 g/mL)

Question 10: Density of the Rock

Given:

  • Mass of empty graduated cylinder: 50 g
  • Mass of graduated cylinder with 30 mL water: 120 g
  • Mass of graduated cylinder with water and rock: 250 g
  • Water level after adding rock: 75 mL

To find: Density of the rock

Solution:

i. Find the mass of the water:

  • Mass of water = Mass with water - Mass of empty cylinder = 120 g - 50 g = 70 g

ii.. Find the volume of the rock:

  • Volume of rock = Final water level - Initial water level = 75 mL - 30 mL = 45 mL

iii. Find the mass of the rock:

  • Mass of rock = Total mass - Mass of water - Mass of cylinder = 250 g - 70 g - 50 g = 130 g

iv.. Calculate the density of the rock:

  • Density = Mass / Volume = 130 g / 45 mL = 2.89 g/mL

Question 11: Layering of Fluids

Given:

  • Fluid A: Mass = 2060 g, Volume = 2000 mL
  • Fluid B: Mass = 672 g, Volume = 850 mL
  • Fluid C: Mass = 990 g, Volume = 1100 mL

To find: How the fluids will be layered in a beaker

Solution:

i. Calculate the density of each fluid:

  • Density of A = 2060 g / 2000 mL = 1.03 g/mL
  • Density of B = 672 g / 850 mL = 0.79 g/mL
  • Density of C = 990 g / 1100 mL = 0.9 g/mL

ii. Arrange the fluids in order of decreasing density:

  • Fluid A: 1.03 g/mL
  • Fluid C: 0.9 g/mL
  • Fluid B: 0.79 g/mL

iii. Based on the densities, the fluids will layer with the densest fluid at the bottom and the least dense fluid at the top.

The fluids will be layered as follows:

  • Bottom: Fluid A (1.03 g/mL)
  • Middle: Fluid C (0.9 g/mL)
  • Top: Fluid B (0.79 g/mL)

User Slorinc
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