Yes , there is restriction on the domain for the function, f (x) = 1/(x- 7)
For explaining it i want to give a example to you.
Let us put x = 7,
Then we get,
f (x) = 1/(7-7)
= 1/0
It is indeterminant form or not defined form☝
So we cannot put x = 7 in this function.
And as we know that the values we put is called domain.
Therefore, there is restriction on uts domain.
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