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A reaction mechanism has the following elementary step as the slow step: B2A What is the rate law for this elementary step? O rate = k[B] O rate = k[A] [B]2 O rate = k[A] O rate = k [A] [B] O rate = k[A
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A reaction mechanism has the following elementary step as the slow step: B2A What is the rate law for this elementary step? O rate = k[B] O rate = k[A] [B]2 O rate = k[A] O rate = k [A] [B] O rate = k[A]2

User AaronSieb
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Answer:

r = k [ B ]

Step-by-step explanation:

  • B → 2A

⇒ r = k [ A ]/2 = k [ B ]

User Synexis
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