Question

The half-life of carbon 14 is 5, 730 years. How much would be left of an original 50-

gram sample after 2, 292 years?

Answer 1

Answer: i have zero clue lol

Answer 2

Given :

The half-life of carbon 14 is 5,730 years.

To Find :

How much would be left of an original 50- gram sample after 2, 292 years.

Solution :

We know, rate law for first order reaction is given by :

`[A] = [A_o]e^(-kt)` ...1)

Here,
`A_o` is initial amount and
`A` is final amount.

And
`k = (ln\ 2)/(t_(0.5))`

Putting value of half time in above equation, we get :

`k = (ln\ 2)/(5730)\\\\k = 1.21*10^(-4) \ /s`

Putting value of k in equation 1) , we get :

`[A] = 50* e^{-1.21* 10^(-4)* 2292} = 37.89\ gm\\\\`

Hence, this is the required solution.