Answer:
Valance electron in
will be zero
Step-by-step explanation:
We know that atomic number of cesium is 55
The electronic configuration of Cs
![1s^2,2s^2,2p^6,3s^2,3p^6,3d^(10),4s^2,4p^6,4d^(10),5s^2,5p^6,6s^1](https://img.qammunity.org/2020/formulas/chemistry/college/24oxynbr2szg8vd902my9jlpxxr0t8xclt.png)
Currently therte is one valance electron in Cs
We have given
+ sign indicates that cesium losses one electron means now it have no valance electron.
So valance electron in
will be zero