Question

How many grams Glycylglycine (molecular mass 132.119 grams/mole) are required to make 1 liter at 0.5 Molar concentration. If you need this solution at pH 9.0 is anything else required? (2 pts)

Answer 1

Step-by-step explanation:

The given data is as follows.

Concentration of solution = 0.5 M

Volume of solution = 1 L

Molar mass of Glycylglycine = 132.119 g/mol

As molarity is the number of moles present in liter of solvent.

Mathematically, Molarity =
`\frac{\text{No. of moles}}{\text{Volume}}`

Hence, calculate the number of moles as follows.

No. of moles = Molarity × Volume

=
`0.5 M * 1 L`

= 0.5 mol

Therefore, mass of glycylglycine = mol × molar mass

=
`0.5 mol * 132.119 g/mol`

= 66.06 g

Thus, we can conclude that 66.06 g glycylglycine is required.