Answer:
The group speed is
.
Step-by-step explanation:
Given that,
Phase speed
![v_(p)=(g)/(\omega)](https://img.qammunity.org/2020/formulas/physics/college/cqqcs2lvxzixlhlil8ikbbju6otz4qekfk.png)
![\omega=(2\pi)/(T)](https://img.qammunity.org/2020/formulas/physics/high-school/jdv8dwcawmf04t5e2701pgtk9w9oqvyi6f.png)
Where, T = period of the wave
g =acceleration due to gravity
We need to calculate the group speed
Using formula of phase speed
![v_(p)=(\omega)/(k)](https://img.qammunity.org/2020/formulas/physics/college/cp9u99k7oa75gkqbmqsax0075hpu61vny2.png)
Put the value of
![v_(p)](https://img.qammunity.org/2020/formulas/physics/college/cql1xhlfrjltvrvc77mi6w4vmoyuezxhyw.png)
![(g)/(\omega)=(\omega)/(k)](https://img.qammunity.org/2020/formulas/physics/college/zawozor204cs2yln68j82uwgmadc9pmsi1.png)
....(I)
We need to calculate the group speed
Using formula of group speed
![v_(g)=(d\omega)/(dk)](https://img.qammunity.org/2020/formulas/physics/college/yyuth50gt9z6j0lmuxi8ujbmrqadsg2sxq.png)
![v_(g)=(d)/(dk)(√(gk))](https://img.qammunity.org/2020/formulas/physics/college/qibhl30woka3z3dejmbr7idrc2zw5reo87.png)
On differentiating
![v_(g)=(1)/(2)\sqrt{(g)/(k)}](https://img.qammunity.org/2020/formulas/physics/college/v0m1f1064hkcv4d778wklc62q8w1n0vtr8.png)
Put the value of k from equation (I)
![v_(g)=(1)/(2)\sqrt{(g)/((\omega^2)/(g))}](https://img.qammunity.org/2020/formulas/physics/college/btblg97juh12nz8kcrlw7ia6gp7nu4fgtd.png)
![v_(g)=(1)/(2)*(g)/(\omega)](https://img.qammunity.org/2020/formulas/physics/college/lyyb57xflzjo41ld34vp7dmxjot77mmunk.png)
![v_(g)=(v_(p))/(2)](https://img.qammunity.org/2020/formulas/physics/college/hvybuthdohc4yzfopxdjzjiwztbshrd3tj.png)
Hence, The group speed is
.