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Fe2O3 + 5C + 3O2 = 2Fe + 5CO2

Calculate the number of moles of FeO2 that would be needed to react exactly with 0.49 mol of O2

User MHSaffari
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Answer:

0.33 mol of Fe₂O₃

Step-by-step explanation:

For the reaction given in the question -

Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂

Balancing the above reaction ,

2Fe₂O₃ + 5 C + 3O₂ → 2 Fe + 5 CO₂

According to the above balanced reaction ,

2 mol of Fe₂O₃ will react with 5 mol of C and 3 mol of O₂ to give 2 mol of Fe and 5 mol of CO₂ .

Hence ,

2 mol of Fe₂O₃ will react with 3 mol of O₂

or ,

3 mol of O₂ ------ 2 mol of Fe₂O₃

Using unitary method ,

1 mol of O₂ ------ 2 / 3 mol of Fe₂O₃

From the question , for 0.49 mol of O₂ ,

0.49 mol of O₂ ------- 2 / 3 * 0.49 mol of Fe₂O₃ = 0.33 mol of Fe₂O₃

User SoTm
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