Answer: 4.1
Explanation:
Given : An urn contains 10 balls with the number ‘5’ printed on them, 6 balls with ‘4’ printed on them, and 4 balls with ‘2’ printed on them.
Total balls = 10+6+4=20
Let A , B and C are the events of drawing ball with the number ‘5’, ball with the number ‘4’ and ball with the number ‘2’ respectively.
Then,
![P(A)=(10)/(20)=0.5\\\\ P(B)=(6)/(20)=0.3\\\\ P(C)=(4)/(20)=0.2](https://img.qammunity.org/2020/formulas/mathematics/college/lilb79o0036entu4blh0liknpdk39xc2d5.png)
If X is the number observed.
Since
![E[X]=\sum_(i=1)^(n)x_ip_i](https://img.qammunity.org/2020/formulas/mathematics/college/j2acb2djzhsb4nld1nqjch5om2y1s46hw4.png)
Then,
![E[X]=5* P(A)+4* P(B)+2* P(C)\\\\=5* 0.5+4* 0.3+2* 0.2\\=4.1](https://img.qammunity.org/2020/formulas/mathematics/college/4msx9om5j1m5kagidm3c9ypdi8s3mxmbzm.png)
Hence, E[X]=4.1