Answer: The mass of iron (III) nitrate is 11.16 g/mol
Step-by-step explanation:
To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

We are given:
Molarity of solution = 0.3556 M
Molar mass of Iron (III) nitrate = 241.86 g/mol
Volume of solution = 129.8 mL
Putting values in above equation, we get:

Hence, the mass of iron (III) nitrate is 11.16 g/mol