Question

Balance 6Sb +6Cl2– 6SbCl3

Answer 1

Balancing is making the number of atoms of each element same on both the sides (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript

For example
`5 Ca_1 Cl_2` contains

5 × 1 = 5,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example
`3Ca_3 (P_1 O_4 )_2` we multiply coefficient
`*` subscript
`*` number outside the bracket.......... to find the number of atoms

(Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9, Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present.

So

Let us balance the equation given

`1Sb +1Cl_2 > 1SbCl_3`

(Unbalanced)

Reactant side - Number of atoms of each element - Product side

1 - Sb - 1

2 - Cl - 3

So we have on the product side odd number of Cl to convert to even number, multiply
`SbCl_3` by 2

The equation changes to

`1Sb +1Cl_2> 2SbCl_3`

Reactant side - Number of atoms of each element - Product side

1 - Sb - 2

2 - Cl - 6

Multiplying Sb by 2 and
`Cl_2`

`2Sb +3Cl_2> 2SbCl_3`

The equation is balanced now!!!!

Reactant side - Number of atoms of each element - Product side

2 - Sb - 2

6 - Cl - 6

Balanced.