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Given the following balanced redox reaction: 2 KMnO,+16 HCI2KCI+2 MnCl, +8 H20+5 Cl What is the stoichiometric factor relating KM O, and MnCl, representing the actual numbers of moles of each species that
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Given the following balanced redox reaction: 2 KMnO,+16 HCI2KCI+2 MnCl, +8 H20+5 Cl What is the stoichiometric factor relating KM O, and MnCl, representing the actual numbers of moles of each species that react and are produced according to the equation above?

User Tinu Jos K
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Final answer:

The stoichiometric factor relating KMnO4 and MnCl2 is 1:1.

Step-by-step explanation:

The stoichiometric factor relating KMnO4 and MnCl2 can be determined from the balanced chemical equation given.

According to the equation, 2 moles of KMnO4 react and produce 2 moles of MnCl2. This means that the stoichiometric factor relating KMnO4 and MnCl2 is 1:1, where 1 mole of KMnO4 reacts with and produces 1 mole of MnCl2.

User Graham Streich
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