1 Answer

Terry Li · Answer 1 · 2020-08-12T11:17:55+0000

Step-by-step explanation:

Molecular mass of sugar =
C_(12)H_(22)O_(11) : = 432 g/mol

Atomic mass of carbon atom = 12 g/mol

Atomic mass of hydrogen atom = 1 g/mol

Atomic mass of oxygen atom = 16 g/mol

a) Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}* \text{Atomic mass of element}}{\text{molecular mass of compound}}* 100$

Percentage of carbon by weight in
C_(12)H_(22)O_(11) :

$(12* 12 g/mol)/(342 g/mol)* 100=42.10\%$

Percentage of hydrogen by weight in
:

$(22* 1g/mol)/(342 g/mol)* 100=6.43\%$

Percentage of oxygen by weight in
C_(12)H_(22)O_(11) :

$(11* 16g/mol)/(342 g/mol)* 100=51.46\%$

b) Percentage of mole each of the elements present in sugar:

=
$\frac{\text{Moles of atoms of an element}}{\text{total moles of all types of atoms}}* 100$

In mole of sugar we have 12 moles of carbon atom , 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

Percentage of carbon by mole in
:

$(12 mol)/(45 mol)* 100=26.66\%$

Percentage of hydrogen by mole in
:

$(22 mol)/(45 mol)* 100=48.88\%$

Percentage of oxygen by mole in
:

$(11 mol)/(45 mol)* 100=24.44\%$

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