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The fuel used in many disposable lighters is liquid butane, C4H10. How many carbon atoms are in 2.00 g of butane?

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Answer:

The answer to your question is: 8.31 x 10 ²² atoms

Step-by-step explanation:

butane C₄H₁₀

carbon atoms in 2 g of butane

MW C₄H₁₀ = (4 x 12) + (1 x10) = 48 + 10 = 58 g

58 g of butane ------------------- 48 g of C

2 g of butane ----------------- x

x = (2 x 48) / 58 = 1.655 g of C

1 mol C ------------------- 12 g

x ------------------ 1.655 g

x = (1.655 x 1) / 12 = 0.14 mol of C

1 mol of C ------------------- 6.023 x 10 ²³ atoms

0.14 mol of C ---------------- x

x = ( 0.14 x 6.023 x 10 ²³) / 1

x = 8.31 x 10 ²² atoms

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