Question

An electric field of 710,000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -6.00 C at this spot? (14C - 10 6C) Give your answer in Si unit rounded to two decimal places

Answer 1

`4.26*10^6N`

Step-by-step explanation:

A charge within an electric field E experiences a force proportional to the field whose module is F = qE, whose direction is the same, if the charge is negative, it experiences a force in the opposite direction to the field and if the charge is positive, experience a force in the same direction of the field.

In our case we are interested in the magnitude of the force, therefore the sign of the charge has no relevance

`\left | F \right |=\left |q  \right |  \left |E\right |\\\left | F \right |=6.00C*710000(N)/(C)=4.26*10^6N`