Question

A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is 0.19 m below the level of the water that is in the tank. If the top of the trough is open to the atmosphere, what is the speed of the water as it leaves the hole? Assume that the trough is large enough that the velocity of the water at the top is zero. The acceleration of gravity is 9.81 m/s 2 . Answer in units of m/s.

Answer 1

`v=1.93m/s`

Step-by-step explanation:

From the concept of fluids mechanics we know that if a tank has a hole at the bottom, the equation that we need to use is:

`v=√(2gh)`

Since we know gravity and its hight

`v=\sqrt{2*(9.81m/s^(2))(0.19m) }=1.93m/s`