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If y = 0.02 sin (30x – 200t) (SI units), the frequency of the wave is

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Answer:

31.831 Hz.

Step-by-step explanation:

Given:


  • \rm y = 0.02\sin(30x-200 t).

The vertical displacement of a wave is given in generalized form as


\rm y = A\sin(kx -\omega t).

where,

  • A = amplitude of the displacement of the wave.
  • k = wave number of the wave =
    (2\pi )/(\lambda).

  • \lambda = wavelength of the wave.
  • x = horizontal displacement of the wave.

  • \omega = angular frequency of the wave =
    \rm 2\pi f.
  • f = frequency of the wave.
  • t = time at which the displacement is calculated.

On comparing the generalized equation with the given equation of the displacement of the wave, we get,


\rm A=0.02.\\k=30.\\\omega =200.\\

therefore,


\rm 2\pi f=200\\\\\Rightarrow f = (200)/(2\pi)=31.831\ Hz.

It is the required frequency of the wave.

User Rafael Borja
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