Answers and Explanations:
1). 50 ml of 1% acetic acid
Solute: acetic acid (Formula: CH₃COOH)
Solvent: water (H₂0), if nothing else is indicated, the solvent is always water)
1% acetic acid means that there are 1 gram of acetic acid in 100 ml of solution: 1 g CH₃COOH/100 ml solution. We need 50 ml of solution, thus we can divide into 2 both numerator and denominator in the relation as follows:

To prepare the solution: weigh 0.5 g of acetic acid and dissolve in 50 ml water.
2) 25 ml of 10% sodium chloride
Solute: sodium chloride (NaCl)
Solvent: water (H₂O)
The same as in 1), we divide in this case into 4 both numerator and denominator (to obtain the volume we need: 100ml/4= 25 ml)

To prepare the solution: weigh 2.5 g of NaCl and dissolve in 25 ml water.
3) 10 ml of 0.1% quinine sulfate
Solute: quinine sulfate (QS) (Formula: C₂₀H₂₄N₂O₂)
Solvent: water (H₂O)

To prepare the solution: weigh 0.01 g of quinine sulfate and dissolve in 10 ml water.
4) 1 L of 5% sucrose
Solute: sucrose (Formula: C₁₂H₂₂O₁₁)
Solvent: water (H₂O)

To prepare the solution: weigh 50 g of sucrose and dissolve in 1000 ml water (1000 ml= 1 L).
5) 60 ml of 0.2% o-dianasidine in methanol
Solute: o-dianasidine (ODS) (Formula: C₁₄H₁₆N₂O₂)
Solvent: methanol (CH₃OH). Note that in this case it is indicated that the solvent is not water, but it is methanol.

To prepare the solution: weigh 0.12 g of ODS and dissolve in 60 ml methanol.
6) 50 ml of 3% sodium hydroxide
Solute: sodium hydroxide (NaOH)
Solvent: water (H₂O)

To prepare the solution: weigh 1.5 g of NaOH and dissolve in 50 ml water.
7) 75 ml of 1% sodium nitroferrocyanide
Solute: sodium nitroferrocyanide (NFC) (Formula: C₅FeN₆Na₂O)
Solvent: water (H₂O)

To prepare the solution: weigh 0.75 g of NFC and dissolve in 75 ml water.