Answer:
There are 90 ways to distribute the prizes
Explanation:
* Lets explain how to solve the problem
- There are 6 different prize distributed equally among 3 super students
∵ There are 6 prize are to be equally distributed among 3 students
∴ Each student will get ⇒ 6 ÷ 3 = 2
∴ Each student takes 2 prize
* Order doesn't matter here because the 3 students are super
so we can start with any one of them
# The 1st student will get 2 prize from 6
∴ The choices = 6C2
# The 2nd student will get 2 prize from remaining 4 prize
∴ The choices = 4C2
# The 3rd student will get 2 prize from remaining 2 prize
∴ The choices = 2C2
* To find the total choices multiply the three choices above
∴ The total choices = 6C2 × 4C2 × 2C2
∴ The total choices = 15 × 6 × 1 = 90 choices
* There are 90 ways to distribute the prizes