Question

If the temperature changes by 100 K, by how much does it change in °C?

Answer 1

100K − 273.15 = -173.1°C

Answer 2

∆T is same in both K as well as in ℃ (Answer)

Step-by-step explanation:

Temperature change is represented by ∆T

∆T=
`T_(final) - T_(initial)`

∆T is same in both K as well as in ℃ (Answer)

Suppose if the temperature increases from 0℃ to 10℃

∆T = 10℃ - 0℃ = 10℃

In Kelvin

`T_(final)` = 10℃ + 273 = 283K

`T_(initial)` = 0℃ + 273 = 273 K

∆T = 283 K - 273 K = 10 K .

Thus, it is proved that ∆T is same in both K as well as in ℃ (Answer)