Question

When point charges q = +8.4 uC and q2 = +5.6 uC are brought near each other, each experiences a repulsive force of magnitude 0.66 N. Determine the distance between the charges.ns

Answer 1

Distance between the charges, r = 0.8 meters

Step-by-step explanation:

Given that,

Charge 1,
`q_1=+8.4\ \mu C=+8.4* 10^(-6)\ C`

Charge 2,
`q_2=+5.6\ \mu C=+5.6* 10^(-6)\ C`

Repulsive force between charges, F = 0.66 N

Let r is the distance between charges. The formula for the electrostatic force is given by :

`F=k(q_1q_2)/(r^2)`

`r=\sqrt{(kq_1q_2)/(F)}`

`r=\sqrt{(9* 10^9* 8.4* 10^(-6)* 5.6* 10^(-6))/(0.66)}`

r = 0.8009 meters

or

r = 0.8 meters

So, the distance between the charges i 0.8 meters. Hence, this is the required solution.