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You need to determine the mass of an aqueous solution. You determine the mass of your 10.0 mL graduated cylinder to be 23.529 g. After adding a volume of 3.27 mL of solution to the cylinder, you reweigh it and determine the new mass to be 26.694 g. What is the mass of the aqueous solution? WebAssign will check your answer for the correct number of significant figures. g What is the density of the aqueous solution? WebAssign will check your answer for the correct number of significant figures. g/mL

2 Answers

5 votes

Final answer:

To determine the mass of the aqueous solution, the mass of the empty graduated cylinder is subtracted from the mass with the solution, yielding 3.165 g. The density is calculated by dividing this mass by the volume (3.27 mL) of the solution, which gives approximately 0.969 g/mL.

Step-by-step explanation:

Determining the Mass and Density of Aqueous Solution

To find the mass of the aqueous solution, you subtract the mass of the empty graduated cylinder (23.529 g) from the mass of the cylinder with the solution (26.694 g). Therefore, the mass of the aqueous solution is:

26.694 g – 23.529 g = 3.165 g

The mass has been measured with four significant figures. The volume of the aqueous solution is 3.27 mL, which has three significant figures. To calculate the density of the solution, you divide the mass of the solution by the volume of the solution:

Density = Mass of Aqueous Solution / Volume of Aqueous Solution

Density = 3.165 g / 3.27 mL ≈ 0.9685 g/mL

The density should be reported with the same number of significant figures as the measurement with the least number of significant figures. Therefore, the density of the aqueous solution is approximately 0.969 g/mL.

User Gerriet
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3 votes

Answer:

The density of aqueous solution is 0.968 g/mL

Step-by-step explanation:

For calculating density we need to have the mass and the volume and apply the following equation:

Density = Mass (g) / volume (mL)

We have the volume of the solution, 3.27 mL. The mass come from subtracting 26.694 - 23.529 = 3.165 g

Applying Density equation:

Density = 3.165 g / 3.27 mL = 0.96788990825 ....

The value has a higher quantity of significant figures is the mass, so, the result must be to have the same figures and approximate the result in the last digit to the next or to the previous number. In this case, the mass has 3 number of significant figures and the third significant number in the result must be 8 because the fourth number is major than 5. If it were less, the third significant number were 7.

I hope my answer helps you

User Sumanth Varada
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