Answer:
135 to nearest whole number.
Explanation:
∑ 5(4/3)^(k-1) from k = 1 to k = 8.
First term = 5 , second term = 5*4/3
This is a Geometric series with first term a1 = 5 and common ratio r = 4/3.
The sum of n terms = a1(r^n - 1) / (r - 1).
The sum of 8 terms is given by 5 * (4/3)^8 - 1) / ( 4/3 - 1)
= 135 to the nearest whole number.