Question

I need to find the approximate sum. ​

Answer 1

135 to nearest whole number.

Explanation:

∑ 5(4/3)^(k-1) from k = 1 to k = 8.

First term = 5 , second term = 5*4/3

This is a Geometric series with first term a1 = 5 and common ratio r = 4/3.

The sum of n terms = a1(r^n - 1) / (r - 1).

The sum of 8 terms is given by 5 * (4/3)^8 - 1) / ( 4/3 - 1)

= 135 to the nearest whole number.