Question

The scores of an eighth-grade math test have a normal distribution with a mean u = 83 and a standard deviation o = 5. If

Din's test score was 92, which expression would she write to find the Z-score of her test score?
92-83
O2- 83
5
O z: 83-92
O z- 92-83
0
92

Answer 1

92-83/5

Explanation:

Answer 2

`z=(92-83)/(5)`

Explanation:

* Lets explain how to find the z-score

- If the data have normal distribution with a mean μ and a standard

deviation σ and we need to find the z-score for score x,then

`z=(x-u)/(o)`

* Lets solve the problem

- The scores of an eighth-grade math test have a normal distribution

- The mean is 83

- The standard deviation is 5

- Din's test score was 92

- We need to find z-score of Din's test score

∵ x = 92

∵ μ = 83

∵ σ = 5

∴
`z=(92-83)/(5)`