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Solve this ordinary differential equation dy/dx = (x^2-x+)/(y-1)

1 Answer

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This equation is easily separable as


(\mathrm dy)/(\mathrm dx)=(x^2-x+k)/(y-1)\implies(y-1)\,\mathrm dy=(x^2-x+k)\,\mathrm dx

where the
k term is assumed to be some constant that was omitted from the question. Integrating both sides gives


\frac{y^2}2-y=\frac{x^3}3-\frac{x^2}2+kx+C

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