Question

An FM radio station broadcasts at 98 MHz. what is the energy of each photon in Joule? Use h= 6.6 X10^-34 J*s for Planck constant.

Answer 1

Energy of each photon will be
`6.468* 10^(-24)J`

Explanation:

We have given frequency
`\\u` = 98 MHz
`=98* 10^6Hz`

We have given plank's constant
`h=6.6* 10^(-34)j-s`

We have to find the energy of each photon

Energy of photon is given by
`E=h\\u`, here h is plank's constant and
`\\u` is frequency

So energy
`E=6.6* 10^(-34)* 98* 10^6=6.468* 10^(-24)J`