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Find the most general antiderivative of the function. (Check yo f(x) = 3^x + 7 sinh(x) F(x) = Need Help? Watch It Talk to a Tutor

User Adarsh V C
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3 votes

Answer:

The most general anti-derivative of the function is
(3^x)/(\ln \left(3\right))+7\cosh \left(x\right)+C

Explanation:

Definition. An anti-derivative of a function f(x) is a function whose derivative is equal to f(x). That is, if F′(x) = f(x), then F(x) is an anti-derivative of f(x).

We can use this theorem

If F is an anti-derivative of f on an interval I, then the most general anti-derivative of f on I is

F(x) + C,

where C is an arbitrary constant.

and
\int\limits {f(x)} \, dx=F(x) means
F'(x) = f(x)

To find the anti-derivative of a function you need to follow these steps:

  • Apply the sum rule
    \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx


\int \:3^x+7\sinh \left(x\right)dx = \int \:3^xdx+\int \:7\sinh \left(x\right)dx

  • The anti-derivative of
    3^x is


\int \:3^xdx = (3^x)/(\ln \left(3\right))

Because
\int a^xdx=(a^x)/(\ln a)

  • The anti-derivative of
    7 \cdot sinh(x) is


\int \:7\sinh \left(x\right)dx=7\cosh \left(x\right)

Because
\int \sinh \left(x\right)dx=\cosh \left(x\right)

So the most general anti-derivative of the function is
(3^x)/(\ln \left(3\right))+7\cosh \left(x\right)+C

User Niyas
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