Answer:
Q=127.66W
L=9.2mm
Step-by-step explanation:
Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.
To solve any problem related to heat transfer, the general equation is used
Q = delta / R
Where
Q = heat
Delta = the temperature difference
R = is the thermal resistance by conduction, convection and radiation
to solve this problem we propose the previous equation
Q = delta / R
later we find R
![R=[tex]r=(6L1)/(AK1) +(5L2)/(AK2)+(1)/(Ah)](https://img.qammunity.org/2020/formulas/engineering/college/ea16a38fxiceijvvrpzgf4xszwic9cj858.png)

Q=(25-(-5))/0.235=127.66W
part b
we use the same ecuation with Q=127.66
Q = delta / R
Δ
