Question

(x+1)(2x-4)(1/x+1) = (x+1)(2x-4)(1-5/2x-4)

Answer 1

`(x+1)(2x-4)((1)/(x)+1)=(x+1)(2x-4)(1-(5)/(2x)-4)\\(x+1)(2x-4)((1)/(x)+1)-(x+1)(2x-4)(1-(5)/(2x)-4) = 0\\(x+1)(2x-4)((1)/(x)+1-(1-(5)/(2x)-4))=0\\(x+1)(2x-4)((1)/(x)+1-(-3(5)/(2x)))=0\\(x+1)(2x-4)((1)/(x)+1+3+(5)/(2x))=0\\(x+1)(2x-4)((1)/(x)+4+(5)/(2x))=0\\(x+1)(2x-4)((5x^(2)+8x+2)/(2x) )=0\\`

`x+1=0\\x=-1\\\\2x-4=0\\x=2\\\\(5x^(2)+8x+2)/(2x)=0\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}`

Answer:

`x=-1\\x=2\\x=\frac{-4+\sqrt[]{6}}{5}\\x=\frac{-4-\sqrt[]{6}}{5}`

Hope this was helpful.