Question

A rugby player passes the ball 7.88 m across the field, where it is caught at the same height as it left his hand. (Assume the player is facing the +x direction.) (a) At what angle (in degrees counterclockwise from the +x-axis) was the ball thrown if its initial speed was 13.1 m/s, assuming that the smaller of the two possible angles was used? ° counterclockwise from the +x-axis (b) What other angle (in degrees counterclockwise from the +x-axis) gives the same range? ° counterclockwise from the +x-axis

Answer 1

Step-by-step explanation:

Given

Range of ball =7.88 m

Initial speed=13.1 m/s

and we know

Range of Projectile is

`R=(u^2sin2\theta )/(g)`

`13.1=(13.1^2* sin2\theta )/(9.8)`

`7.88* 9.8=13.1^2* sin2\theta`

`sin2\theta =0.4499`

`2\theta =26.74^(\circ)`

`\theta =13.37 ^(\circ)`

(b)other angle would be complementary of
`\theta`

`=90-\theta =76.63 ^(\circ)`