Answer:
96.5 km/h
Step-by-step explanation:
The average velocity of the train is given by:
![v=(d)/(t)](https://img.qammunity.org/2020/formulas/physics/high-school/jidcwnxn1c0zdocnxtzp97sqgn187ivyra.png)
where
d is the displacement
t is the time taken
For this train, we have:
d = 55 km south (displacement is a vector, so we must also consider the direction)
![t= 34 min \cdot (1)/(60 min/h)=0.57 h](https://img.qammunity.org/2020/formulas/physics/middle-school/sezlsh3eo9928ohz11qmren24djg7dgkdt.png)
Substituting into the equation, we find the average velocity:
![v=(55 km)/(0.57 h)=96.5 km/h](https://img.qammunity.org/2020/formulas/physics/middle-school/4lszdqvpnkfquhmkhv12t89qizg52weevc.png)