Question

Use the grouping method to factor this polynomial x ^ 3 + 2x ^ 2 + 7x + 14

Answer 1

B. (
`x^(2)`+7)(x+2)

Explanation:

The greates common factor between 7 and 14 is 7 so you know that one of the terms is going to be 7....but what times 7 equals 14...2

So we know that in one set of parentheses its going to be (something +2) and in another (something +7)

Well if we know that one is going to be 2, how do we go from 2 to 2
`x^(2)`.....2 times
`x^(2)` equals
`2x^(2)`

So now we know that one set of parentheses is going to be (something + 2) times (
`x^(2)`+7)

So lastly, we have to find out how to get
`x^(3)` but since we already have a
`x^(2)` in the second set of parentheses all we have to do is put a x in the first set because x times
`x^(2) = x^(3)`

Hope this helps!