Question

S is the midpoint of line rt

r has the coordinates of (-10,2)
s has the coordinates of (6,4)
find the coordinates of endpoint t

Answer 1

The coordinates of point t are (22,6)

Explanation:

we know that

The formula to calculate the midpoint between two point is equal to

`s=((x1+x2)/(2),(y1+y2)/(2))`

we have

s(6,4)

(x1,y1)=r(-10,2)

Let

t(x2,y2)

substitute the values

`(6,4)=((-10+x2)/(2),(2+y2)/(2))`

Solve for x2

`6=(-10+x2)/2\\12=-10+x2\\x2=12+10\\x2=22`

Solve for y2

`4=(2+y2)/2\\8=2+y2\\y2=8-2\\y2=6`

therefore

The coordinates of point t are (22,6)