Answer:
Speed of Chris Huber = 30.726 m/s
Time taken by Sam = 5.55 s
Explanation:
Given:
Distance = 200 m
Time taken by Chris Huber = 6.509 s
Now,
Speed of Chris Huber =
![\frac{\textup{Distance}}{\textup{Time}}](https://img.qammunity.org/2020/formulas/mathematics/college/8mrncnfg5930qjcbh3nwfmtczcu14otcn7.png)
or
Speed of Chris Huber =
![\frac{\textup{200 m}}{\textup{6.509 s}}](https://img.qammunity.org/2020/formulas/mathematics/college/sw05ebpj8msfmn3m6csauykd2pftqtfkfp.png)
or
Speed of Chris Huber = 30.726 m/s
Speed of Sam = Speed of Chris Huber + 19.0 km/h
Now,
1 km/hr = 0.277778 m/s
thus,
19.0 km/h = 19.0 × 0.27 = 5.278 m/s
thus,
Speed of Sam = 30.726 + 5.278 = 36.004 m/s
therefore,
Time taken by Sam =
![\frac{\textup{Distance}}{\textup{Speed}}](https://img.qammunity.org/2020/formulas/mathematics/college/v8o3mybvbiyfhwynw4706980wwrsbhns1k.png)
or
Time taken by Sam =
= 5.55 s