Answer:
(a). 5400
(b). 57 - 0.95, 85 - 0.48 and 94 - 0.44
(c). Less load in Flight number 85 and 94.
Step-by-step explanation:
In the question,
Number of seats in a jet = 180
And,
![Passenger\,Load=(Number\,of\,seats\,sold)/(Number\,of\,available\,seats)](https://img.qammunity.org/2020/formulas/mathematics/high-school/z529jbqetbjrzdv2uxpudwm6w7dgzzc8nc.png)
Now,
Flight Number 57 has seats sold = 5130
Flight Number 85 has seats sold = 2592
Flight Number 94 has seats sold = 2376
(a).
Available seat capacity for each flight number in June can be found out by,
Number of days in the month of June = 30 days
Each day the flight has = 180 seats.
So,
Total number of available seat capacity for each flight in June is = 180 x 30 = 5400
Therefore, available seat capacity for each flight = 5400
(b).
Passenger load for each flight can be given by,
For Flight number 57,
![Passenger\,Load=(Number\,of\,seats\,sold)/(Number\,of\,available\,seats)\\Passenger\,Load=(5130)/(5400)\\Passenger\,Load=0.95](https://img.qammunity.org/2020/formulas/mathematics/high-school/hbd30fzmxjg5fb868pdzy14zio3jk1l0fx.png)
For Flight number 85,
![Passenger\,Load=(Number\,of\,seats\,sold)/(Number\,of\,available\,seats)\\Passenger\,Load=(2592)/(5400)\\Passenger\,Load=0.48](https://img.qammunity.org/2020/formulas/mathematics/high-school/u8egk0hao9b17pbe7c0c9z2sma564j29nb.png)
For Flight number 94,
![Passenger\,Load=(Number\,of\,seats\,sold)/(Number\,of\,available\,seats)\\Passenger\,Load=(2376)/(5400)\\Passenger\,Load=0.44](https://img.qammunity.org/2020/formulas/mathematics/high-school/wsn8w5tz285rruvy7xaey91n024b20t9w0.png)
(c).
The recommendation for the Eastern skies can be that the Passenger Load in the Flight number 57 is near to perfect.
But, the Passenger Load in Flight number 85 and 94 is less than required so there is need of selling more seats in the respective airline flights.