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What is a factor of 4x^2-8x-5=0

1 Answer

5 votes

Answer:


-0.5 and
2.5

Explanation:


x_(1,2) = \frac{(-b)/(2) \pm \sqrt{(b^2)/(4)-ac}}{a}= \frac{(8)/(2) \pm \sqrt{(64)/(4)+*4*5}}{4}=(4 \pm √(16+20))/(4)=(4\pm6)/(4)\\=> x_1 = (4+6)/(4) = (10)/(4)=2.5\\=> x_2 = (4-6)/(4)= (-2)/(4) = -0.5

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