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A woman whose body mass is 50 kg rapidly stands from a sitting position with a peak vertical acceleration of 5 m/s2 directed upwards. Relative to her body weight, what percent increase is the peak magnitude of the ground reaction force?

User Nirva
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1 Answer

5 votes

Answer:51.02

Step-by-step explanation:

Given

mass of woman(m)=50 kg

acceleration (a)
=5 m/s^2

Force acting on woman is

mg

Normal reaction(N)

Thus

N-mg=ma

N=m(g+a)


N=50* (9.8+5)=740

Original Normal reaction=mg


N_0=50* 9.8=490 N

% increase
=(N-N_0)/(N_0)


=(740-490)/(490)=0.5102

51.02 %

User Lochana Ragupathy
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