Question

Balance each coefficient as needed 4N2H — 4NH4+N4

Answer 1

Balancing is making the number of atoms of each element same on both the sides (reactant and product side).

To find the number of atoms of each element we multiply coefficient and the subscript

For example
`5 Ca_1 Cl_2` contains

5 × 1 = 5 ,Ca atoms and

5 × 2 = 10, Cl atoms

If there is a bracket in the chemical formula

For example
`3Ca_3 (P_1 O_4 )_2` we multiply coefficient × subscript × number outside the bracket.......... to find the number of atoms (Please note: 3 is the coefficient, and if there is no number given then 1 will be the coefficient )

So

3 × 3 = 9 , Ca atoms

3 × 1 × 2 = 6, P atoms

3 × 4 × 2 = 24, O atoms are present.

So

Let us balance the equation given

`N_2 H_4>NH_3+N_2`

(Unbalanced)

Reactant side element Product

2 N 3

4 H 3

`3 N_2 H_4  > 4 NH_3  + N_2`

(Balanced)

Reactant side element Product

6 N 6

12 H 12

(Balanced)

N2H4 is Hydrazine which produces NH4 ammonia and nitrogen gas on heating that on decomposition.