Question

In ΔOPQ, q = 2 cm, ∠O=59° and ∠P=55°. Find the length of p, to the nearest 10th of a centimeter.

Answer 1

1.8 cm

Explanation:

User the law of Sines.

`(p)/(sin(P)) = (q)/(sin(Q)) \\\\\\p= (q*sin(P))/(sin(Q))`

Q = 180 - ∠O - ∠P = 180-59-55=66

Plug in the numbers using the calculator and get 1.7933470905822447027008654200424‬

Now you need to round it, and you get 1.8 cm