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You need to hire a catering company to serve meals to guests at a wedding reception. Company A charges $500 plus $20 per guest. Company B charges $800 plus $16 per guest. For how many guests are the total costs the same at both companies?

Set up the Cost equations for both companies where g is the number of guests:
C(a) = 20g + 500
C(b) = 16g + 800

User Ron Penton
by
7.9k points

1 Answer

3 votes

Answer:

The answer is 75 guests.

Explanation:

Let the number of guests be represented by g.

Company A charges $500 plus $20 per guest. Equation forms:


500+20g ......(1)

Company B charges $800 plus $16 per guest. Equation forms:


800+16g ......(2)

To know the number of guests to get the total costs of both companies as same, we will equal both equations:


500+20g=800+16g

Solving for g;


20g-16g=800-500

=>
4g=300

=> g = 75

Hence, 75 guests are needed to get costs for both companies same.

User Pramuditha
by
8.0k points
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