Question

For production of crude biodiesel from 250,000 kg/h rapeseed oil reacted with 75,000 kg/h ethanol and 250 kg/h potassium hydroxide with 1 h residence time in a the continuous transesterification process, determine the production yield in kg biodiesel/h assuming 95% conversion of oil.

Answer 1

will be 237,500 kg/h

Step-by-step explanation:

The necessary ingredients to produce the biodiesel from the plant are: the plant, ethanol and the base. So after a period of 1 hour, the biodiesel that is going to be formed is 237, 500 kg/h.

Just apply the rule of three to the main source of biodiesel, that in this case is the rapessed plant and apply the 95 %. Ex:

Biodiesel = 0.95 x 250,000 = 237,500 kg/h