Answer:
Option D. C₆H₈O
Step-by-step explanation:
We can calculate this just using a relation ratio between Hydrogen and Carbon. You may wondering why? well, because the products of the combustion of X, gives CO2 and H2O, and data obtained involves those two elements, so, we can have a ratio of those elements to get the correct formula.
The previous answer was ok, but here is another method
Let's just say that X has the general formula CₓHₙOₐ
When this compound has the combustion we have the following:
CₓHₙOₐ + O₂(excess) ---------> xCO₂ + n/2H₂O
Let's calculate the moles of CO₂ and H₂O:
moles CO₂ = 0.627 / 44 = 0.01425 moles
moles H₂O = 0.1712 / 18 = 9.51x10⁻³ moles
the moles of CO₂ are the same moles of Carbon, and the moles of Hydrogen will be the twice of moles of H₂O according to the equation I wrote so:
moles of H = 9.51x10⁻³ * 2 = 1.90x10⁻² moles
Now, the ratio of Hydrogen and Carbon would be:
H/C = 1.90x10⁻² / 0.01425 = 1.333
So, all we have to do now, is look into the options and see which one has the same ratio of 1.3333:
C5H8O ----> H/C = 8/5 = 1.6
C6H10O2 ----> H/C = 10/6 = 1.67
C10H8O2 ----> H/C = 8/10 = 0.8
C2H4O ----> H/C = 4/2 = 2
C6H8O ----> H/C = 8/6 = 1.3333
Therefore the formula for compound X is C6H8O. This is an alternate method of resolution.