Question

Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentrations of CO and H2 were 0.15 M and0.36 M,respectively. What is the equilibrium concentration of CH3OH? The value of Keq for this reaction is 14.5 at the temperature of the experiment.

Answer 1

The equilibrium concentration of CH₃OH is 0.28 M

Step-by-step explanation:

For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)

The equilibrium constant (Keq) is given for the following expresion:

Keq=
`((CH3OH))/((CO) x (H2)^(2))` =14.5

Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.

We have:

(CH3OH)= ?

(CO)= 0.15 M

(H2)= 0.36 M

So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:

14.5=
`((CH_(3)OH) )/((0.15 M) x (0.36 M) ^(2) )`

14.5 x (0.15 M) x
`(0.36)^(2)` = (CH₃OH)

0.2818 M = (CH₃OH)