Answer:
167,886,383 basketballs
Explanation:
We are asked to find how many basketballs would take to circle around the equator. We have given the earth's radius. So, we need the formula to obtain it's perimeter. Thus:
![Perimeter = Pi*diameter [m]\\Where Pi = 3.14](https://img.qammunity.org/2020/formulas/mathematics/high-school/v4a93mqjaeh1doq0j6prtpbieyaeyvi8ep.png)
Earth's diameter is simply radius*2. It means:
![P= 3.14*6400*2 = 40,192 [km]](https://img.qammunity.org/2020/formulas/mathematics/high-school/lvnpsddfupiufbfaadn16msz3f46nwmcnd.png)
On the other hand, we have a basketball crcumference; however, we need to obtain its diameter so that we can later calculate how many basketballs fit on earth's equator by simply dividing earth's circumference by a basketball's diameter.
Diameter of a basketball:
![D= Perimeter /Pi [m]](https://img.qammunity.org/2020/formulas/mathematics/high-school/q9gd7hqf1xbcsxq7pxdgzdxwvjqkpg3rva.png)
We need to change units to fit in the international system.
29.6 in to cm =
![29.6*2.54 = 75.184 [cm]](https://img.qammunity.org/2020/formulas/mathematics/high-school/krh5hsdbyxu83reo40n6csh88jialsyjxa.png)
Then:
![Diameter=75.184/3.14 = 23.94 [cm]](https://img.qammunity.org/2020/formulas/mathematics/high-school/9b4n5iajl3bgqxapooca0iz4pz6tg075t0.png)
We have to convert earth's perimeter in km to cm:
![Equator=40192[km]*100000=4,019,200,000 [cm]](https://img.qammunity.org/2020/formulas/mathematics/high-school/71s6lpv0qa7zr17lnrhsbeoht2davxok36.png)
Finally, dividing total earth's circumference by a basketball diameter:
![Totalbasketballs=4,019,200,000/23.94= 167,886,383 [basketballs]](https://img.qammunity.org/2020/formulas/mathematics/high-school/xvmu6dpzqqbqnxkshiummiq882gro5lg6e.png)