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A space vehicle deploys its re–entry parachute when it's traveling at a vertical velocity of –150 meters/second (negative because the parachute is going down.) It comes to rest at 0 meters/second after 30 seconds. What's the average acceleration of the shuttle during this time span?

User Vella
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Answer:


a=5m/s^2

Step-by-step explanation:

Aceleration is a change on the velocity of the object in a given time.

For this case: the initial velocity is


v_(1)=150m/s

and the final velocity is :


v_(2)=0 m/s

so, the change in velocity is:


\Delta v =v_(2)-v_(1)=0m/s - (-150m/s) =  150 m/s

and the change in time , according to the problem:


\Delta t=30s

So, the aceleration is:


a=(\Delta v)/(\Delta t) = (150m/s)/(30s) = 5m/s^2

User Jessicah
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