Question

Compute your average velocity in the following two cases: (a) You walk 64.6 m at a speed of 1.20 m/s and then run 64.6 m at a speed of 3.53 m/s along a straight track. (b) You walk for 1.00 min at a speed of 1.20 m/s and then run for 1.78 min at 3.53 m/s along a straight track.

Answer 1

Explanation:

Given

(a)distance
`(s_1)=64.6 m`

speed=1.2 m/s

`s_2`=64.6 at 3.53 m/s

total time
`=(64.6)/(1.2)+(64.6)/(3.53)`

=53.83+18.3=72.13 s

Average velocity
`=(Displacement)/(time)`

`V_(avg)=(129.2)/(72.13)=1.79 m/s`

(b)total distance
`=60* 1.2+106.8* 3.53=72+377.004=449 m`

Average velocity
`=(Displacement)/(time)`

`v_(avg)=(449)/(166.8)=2.69 m/s`