Question

A child uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. The cap travels a horizontal distance of 1.30 m in 1.20 s. What was the initial speed of the bottle cap, just after leaving the rubber band, in m/s

Answer 1

Initial velocity will be 1.356 m/sec

Step-by-step explanation:

Let the initial speed = u

Angle at which rubber band is launched = 37°

Horizontal component of initial velocity
`u_x=ucos\Theta =ucos37^(\circ)=0.7986u`

Time is given as t = 1.20 sec

Distance in horizontal direction = 1.30 m

We know that distance = speed × time

So time
`t=(distance)/(speed)`

`1.20=(1.3)/(0.7986u)`

`u=1.356m/sec`

So initial velocity will be 1.356 m/sec