Answer:
![\lambda=3.15\ m](https://img.qammunity.org/2020/formulas/physics/high-school/q1c5xw6bpxodqafv5p59f4o3plbeie9rkk.png)
Step-by-step explanation:
Frequency of the FM,
![f=95\ MHz=95* 10^6\ Hz](https://img.qammunity.org/2020/formulas/physics/high-school/4asivp9trtbosb1cuszj0v41flhnq76p01.png)
We need to find the wavelength of the radio waves from this station. The relationship between the frequency and the wavelength is given by :
![\lambda=(c)/(f)](https://img.qammunity.org/2020/formulas/physics/college/bvf2efxdcei63o2p5hc47z9087chl772m8.png)
c is the speed of light
![\lambda=(3* 10^8\ m/s)/(95* 10^6\ Hz)](https://img.qammunity.org/2020/formulas/physics/high-school/pnaari9f7wq9k2kvjrj8ff4buqmrovi56h.png)
![\lambda=3.15\ m](https://img.qammunity.org/2020/formulas/physics/high-school/q1c5xw6bpxodqafv5p59f4o3plbeie9rkk.png)
So, the wavelength of the radio waves from this station is 3.15 meters. Hence, this is the required solution.