Answer:
all real numbers except the number 2 and number 1
Explanation:
we have
![f(x)=(3x)/((x-1)(x-2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/20uvloj41b68feefpqn4jbrqzg0jkm4mu5.png)
we know that
In a quotient, the denominator cannot be equal to zero
so
![(x-1)(x-2)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1j4ae6bpn5v5x2hbqb3ybld0fnh4em9lur.png)
Solve for x
The values of x are
x=2, x=1
so
The domain of the function is all real numbers except the number 2 and number 1
In interval notation
(-∞,1) ∩ (1,2) ∩ (2,∞)