Question

It is estimated that 26 large pizzas are about right to serve 66 students of a physics club meeting. How many pizzas would be required if the group, because of a conflicting math club meeting, was only going to have 38 students in attendance?

Answer 1

To solve the problem, use a proportion to find that approximately 15.03 large pizzas would be needed for 38 students. However, since you can't have a partial pizza, 16 pizzas should be ordered to ensure there's enough for each student, thus adhering to the principle where quantity demanded equals quantity supplied (Qd = Qs).

Step-by-step explanation:

To determine how many large pizzas would be required for 38 students when it is known that 26 pizzas are suitable for 66 students, we can set up a proportion because the number of pizzas needed varies directly with the number of students. So, the proportion is:

26 pizzas / 66 students = x pizzas / 38 students

To find the value of x (the number of pizzas needed for 38 students), we multiply both sides of the equation by 38. This gives us:

(26 pizzas / 66 students) * 38 students = x
x = (26 * 38) / 66
x = 15.03

Since we cannot have a partial pizza, we must round up to the nearest whole number. Therefore, 16 large pizzas would be required to serve the 38 students.

Answer 2

The answer to your question is: 15 pizzas

Step-by-step explanation:

data

26 large pizzas ------ 66 students

? large pizzas -------- 38 students

Rule of three

x = 38 (26) / 66 = 14.96 ≈ 15 pizzas